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If for example the roots where x = 2 or x =5 then within the brackets this would be (x-2)(x-5) = 0 and by multiplying out the brackets the quadratic equation comes to x2-7x+10 = 0
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What are the roots of the quadratic equation below?
That depends on the equation.
Using the discriminant determine the number and type of solutions for 3x2-6x plus 30?
6^2 -4(3*30) = -96 meaning that the given quadratic expression has no real roots
A function to compute the real roots of the quadratic equation?
Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a
What is the graph of a quadratic formula?
In general, quadratic equations have graphs that are parabolas. The quadratic formula tells us how to find the roots of a quadratic equations. If those roots are real, they are the x intercepts of the parabola.
Why does the discriminant determine the number and type of the solutions for a quadratic equation?
A quadratic equation is wholly defined by its coefficients. The solutions or roots of the quadratic can, therefore, be determined by a function of these coefficients - and this function called the quadratic formula. Within this function, there is one part that specifically determines the number and types of solutions it is therefore called the discriminant: it discriminates between the different types of solutions.
What are the roots of the quadratic equation below?
That depends on the equation.
How To Determine The Roots Of Quadratic Function?
x = [ -b ± √(b2-4ac) ] / 2a Using this formula you get 2 roots for + and -
Formula of quadratic equation if roots are given?
A quadratic equation has the form: x^2 - (sum of the roots)x + product of the roots = 0 or, x^2 - (r1 + r2)x + (r1)(r2) = 0
Using the discriminant determine the number and type of solutions for 3x2-6x plus 30?
6^2 -4(3*30) = -96 meaning that the given quadratic expression has no real roots
Find the roots of the polynomial given 4x2 - 3x - 5?
No integer roots. Quadratic formula gives 1.55 and -0.81 to the nearest hundredth.
How do you solve a quadratic inequality when the expression is unfactorable?
Use the quadratic formula for the equality. Then, depending on the coefficient of x2 and the nature of the inequality [>, ≥, ≤, <], determine whether you need the open or closed intervals between the roots or beyond the roots.
What are quadratic equations with real roots?
If the discriminant of the quadratic equation is zero then it will have 2 equal roots. If the discriminant of the quadratic equation is greater than zero then it will have 2 different roots. If the discriminant of the quadratic equation is less than zero then it will have no roots.
What are the roots of a quadratic?
The roots of a quadratic function are where the lies interescts with the x-axis. There can be as little as zero.
Why do you use square roots to solve quadratic equations?
Because it's part of the quadratic equation formula in finding the roots of a quadratic equation.
A function to compute the real roots of the quadratic equation?
Where the equation is ax2 + bx + c the roots are given by the solutions to : (-b +/- sqrt(b2 - 4ac))/2a
What is the sum of the roots of the equation -x squared equal to 3x plus 4?
It has no roots because the discriminant of the given quadratic equation is less than zero.
How many roots does a quadratic equation?
2 roots
