64
True
I think you are talking about the x-intercepts. You can find the zeros of the equation of the parabola y=ax2 +bx+c by setting y equal to 0 and finding the corresponding x values. These will be the "roots" of the parabola.
No answers in integers, quadratic formula gives roots as 1.31 and -0.19
People wont understand if you place it in that format, the polynomial should look like x^3+4x^2+2.
None, it involves the square root of a negative number so the roots are imaginary.
4x2-81
4x2+2x+1
It is a polynomial (monomial). It is a polynomial (monomial). It is a polynomial (monomial). It is a polynomial (monomial).
4x2 + 3x - 6 is a second degree polynomial. Since the polynomial function f(x) = 4x2 + 3x - 6 has 2 zeros, it has 2 linear factors. Since we cannot factor the given polynomial, let's find the two roots of the equation 4x2 + 3x - 6 = 0, which are the zeros of the function. 4x2 + 3x - 6 = 0 x2 + (3/4)x = 6/4 x2 + (3/4)x + (3/8)2 = 6/4 + 9/64 (x + 3/8)2 = 105/64 x + 3/8 = ± √(105/64) x = (-3 ± √105)/8 x = -(3 - √105)/8 or x = -(3 + √105)/8 Thus, the linear factorization of f(x) = 4[x + (3 - √105)/8][x + (3 + √105)/8].
The discriminant is 0.
(4x + 5)(x - 3)
zero
kjkjj
64
4x2 - 4 is a polynomial of degree two.
It is: 2x(2x+11)