(x - 3)(x2 + 3x + 9)
Factor out the GCF and get X(X2-X+1).
(2x + 5)(4x2 - 10x + 25)
(x - 1)(x^2 + x + 1)
(2x + 1)(4x^2 - 2x + 1)
GCF(48t, 60st) = 12t.
6t
That's really very easy, because [ 12t3 - 48t ] isn't a question, so there's no answer needed.All it is is a number, whose value depends on the value of 't'.If your class is working on factoring, then the teacher may give you this expression andask you to factor it. If that's what's happening, then [12t3 - 48t] is not the question.The question is: "What is [12t3 - 48t] in factored form ?" That would be12t (t2 - 4)
(t - 15)(t + 3)
8c cubed
They came stock with a 49T or 48T rear sprocket you can choose a replacement with either a 48T, 49T, 50T, or 51T, if you have the old sprocket count the teeth on the sprocket and that tells if it is a 48T, 49T or whatever (48T = 48 teeth)
One is the only factor of 50 that is a cube.
a(a^2 + 1)
Divide all terms by -1: 5t2-12t-9 = 0 (5t+3)(3t-3) = 0 Therefore: t = -3/5 and t = 3 Use the quadratic equation formula.
x times x times x equals x cubed
(2a + c)(4a2 - 2ac + c2)
3^3, or 27, is a factor of 108.