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GCF(48t, 60st) = 12t.

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7y ago

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How do you do the question 12t3- 48t in math?

That's really very easy, because [ 12t3 - 48t ] isn't a question, so there's no answer needed.All it is is a number, whose value depends on the value of 't'.If your class is working on factoring, then the teacher may give you this expression andask you to factor it. If that's what's happening, then [12t3 - 48t] is not the question.The question is: "What is [12t3 - 48t] in factored form ?" That would be12t (t2 - 4)


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How do you factor 12t cubed - 48t?

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What is the square root of 48t to the 9th power?

sqrt[(48t)9] = sqrt(489)*sqrt(t9) = sqrt(488)*sqrt(48)*sqrt(t)*sqrt(t8) = 484*sqrt(48)*sqrt(t)*t4 = 5308416*6.9282*t4*sart(t) = 36777785*t4*sqrt(t)


What is 12t3-48t?

The expression (12t^3 - 48t) can be factored by taking out the greatest common factor, which is (12t). This gives us (12t(t^2 - 4)). Further factoring (t^2 - 4) using the difference of squares results in (12t(t - 2)(t + 2)). Thus, the completely factored form is (12t(t - 2)(t + 2)).


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