0
2x3 - 5x2 + 5x - 2
= x(2x2-5x+3) + 2x - 2
= x(2x-3)(x-1) + 2(x-1)
= (x-1)[x(2x-3)+2]
= (x-1)(2x2-3x+2)
I did it by trial and error, through experience -- no set procedure. (2x2-3x+2) cannot be factored, which is evidenced by calculating (b2-4ac), where a = 2; b=-3; and c=2 from the expression (2x2-3x+2). (b2-4ac) = (9-16) = -7, which has no real square root value. That is, sqrt(-7) is an imaginary number.
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