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Q: How would you factor 12n squared plus 4n cubed minus 7n?

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Squared means 2 in exponents and cubed means 3 in exponents. For example, It saids 5 cubed, than it would be 5.3 .

K-11

16. The way you do it is multiplying the number by its self. If it was four cubed you would do 4x4x4 or 64

That factors to (x + 1)(x - 3) x = -1, 3

(6x + 1)(x + 13)

Related questions

6n(2n - 3)

The factors are -1(2x + 1)(3x + 4)

(8w + 7)(8w - 7)

(2x - 4)(2x + 3) The key is to look for all the factor pairs of 12.

(x squared plus the square root of 2) times (x squared minus the square root of 2).

Squared means 2 in exponents and cubed means 3 in exponents. For example, It saids 5 cubed, than it would be 5.3 .

Since the problem has 4 terms, first you factor x cubed plus 9x squared, then you factor 2x plus 18. So when you factor the first two term, you would get x sqaured (x plus 9). Then when you factor the last two terms and you get 2 (x plus 9). Ypure final answer would be (x squared plus 2)(x plus 9)

( x - y )2There isn't enough information to answer this question because they have two squared variables and you do not know what is being squared. You would first need to either know the value of one of the variables and an equation of the value of both of the variables before you would be able to factor.

x sq equalls 36 and x equalls plus or minus 6

squared as in square units and to the third power it would be cubed as in cubed units

the answer to factorising (a x a3 + 2ab + b2) would be (a4+2ab+b2)

I suppose that would be 14x2 - 7x3. Just take out the common factor, 7x2. Divide each term by this factor to find the other factor.

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