answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}
(5 - x)(5 + x)
(2x + 5)(2x + 5)
(2x - 5)(2x - 5) or (2x - 5) squared
It is: 5(x^2 -16)
8-3p-4 = 2p 4 - 3p = 2p add 3p to both sides 4 = 5p divide both sides by 5 4/5 = p
-5 + 3p - p = -5 + 2p
p = 5
The expression can be simplified to: -8p--29
20p2 + 100p + 125 = 5(4p2 + 20p + 25) = 5(4p2 + 10p + 10p + 25) = 5(2p(2p + 5) + 5(2p + 5)) = 5(2p + 5)(2p + 5) = 5(2p + 5)2
2p + 11p + 5 = 13p + 5 which does not factor. If the expression had been 2p2 + 11p + 5 then this can be factored, 2p2 + 11p + 5 = (2p + 1)(p + 5)
The nitrogen atom has one electron in each of its 2p, 3s, and 3p orbitals, giving it a total of 5 valence electrons.
p2 = 2p + 15 p2 - 2p - 15 = 0 (p - 5)*(p + 3) = 0 so p - 5 = 0 or p + 3 = 0 so p = 5 or p = -3
the total electron distribution in such an atom is 1s--2 2s--2 2p--6 3s--2 3p--5 so, total number of electrons comes out to be 17. so, the element is chlorine. symbol is Cl.
answer is p/5. problem: {[(p^2)-3p]/[(p^2)-6p+9]}/{20/(4p-12)}
The electron configuration for chlorine is 1s^2 2s^2 2p^6 3s^2 3p^5. This configuration indicates that chlorine has 17 electrons, with the last electron in the 3p orbital.
52 is not a factor of 325. 5 squared is a factor of 325.