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6x^2 - 7x - 3
Multiply the first and last coefficients: 6*(-3) = -18
Since this is negative you need two factor of 18 whose difference is the middle coefficient: -7. The factors are 2 and 9. The larger of these has the same sign as the middle coeff and the smaller has the opposite sign. Thus -9 and +2.
So the expression can be written as
= 1/6*(6x - 9)*(6x + 2) = 1/6*3*(2x - 3)*2*(3x + 1) = (2x - 3)*(3x + 1).
Wiki User
∙ 9y ago
Wiki User
∙ 8y ago(3x + 1)(2x - 3)
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Factor the polynomial expression 6x2 plus 11x plus 3?
6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)
How do you factor 10x2- 7x- 3?
(10x + 3)(x - 1)
How do you factor 12x squared -7x -12?
It is: 12x2-7x-12 equals (4x+3)(3x-4) when factored
How do you factor x2 - 7x 12?
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What is the factor of 6x2 13x-5?
6x2+13x-5 = (2x+5)(3x-1) when factored
What are the factor of 6x2 plus 7x-5?
6x2 + 7x - 5 = (3x + 5)(2x - 1)
What is the answer to 3 equals 6x2-7x?
x = -1/3 or 11/2 3 = 6x2 - 7x ⇒ 6x2 - 7x - 3 = 0 ⇒ (3x + 1)(2x - 3) = 0 ⇒ (3x + 1) = 0 → x = -1/3 or (2x - 3) = 0 → x = 11/2
How do you factor 6x2 -7x plus 2?
(2x - 1)(3x - 2)
How do you factor 6x2 plus 14x - 12?
Start by dividing by 2: 2(3x2 + 7x - 6) = 2(3x - 2)(x + 3)
How do you solve this factor problem of x3-6x2 plus 7x-2?
(x - 1)(x^2 - 5x + 2)
6x2-7x 8 -2x22x2?
44
How do you factorise 18x squared-21x-72?
3(6x2-7x-24) by dividing all the terms by 3
How do you solve 6x squared equals negative 7x minus 2?
6x2 = -7x -2 6x2 + 7x + 2 = 0 6x2 + 3x + 4x + 2 = 0 3x(2x + 1) + 2(2x + 1) = 0 (2x + 1)(3x + 2) = 0 2x + 1 = 0 or 3x + 2 = 0 So, x = -1/2 or -2/3
What degree is the polynomial 35-6x2 plus 7x3 plus 5x?
7X^3 Third degree polynomial.
How do you factor 6x2-7x-35?
Since the discriminant, b2-4ac is not a perfect square, there are no rational roots and so these are no rational factors.
How do you find 6x squared plus seven x minus 3 equals zero?
To find the possible values of x in the equation 6x2 + 7x - 3 = 0, you can try to factor the equation: 6x2 + 7x - 3 = 0 6x2 + 9x - 2x - 3 = 0 3x(2x + 3) - 1(2x + 3) = 0 (3x - 1)(2x + 3) = 0 Now you can solve the individual factors for zero, giving you all potential answers to the problem: 3x - 1 = 0 x = 1/3 2x + 3 = 0 x = -3/2 So the possible values of x are -3/2 and 1/3
How do you factorize 6x2-7x-5?
(2x + 1)(3x - 5)
