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6x^2 - 7x - 3

Multiply the first and last coefficients: 6*(-3) = -18

Since this is negative you need two factor of 18 whose difference is the middle coefficient: -7. The factors are 2 and 9. The larger of these has the same sign as the middle coeff and the smaller has the opposite sign. Thus -9 and +2.

So the expression can be written as

= 1/6*(6x - 9)*(6x + 2) = 1/6*3*(2x - 3)*2*(3x + 1) = (2x - 3)*(3x + 1).

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(3x + 1)(2x - 3)

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9y ago
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Q: How do you factor 6x2 - 7x - 3?
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