x2 + 7x + 6 = (x + 6) (x + 1)
x2 - 7x = 60 x2 - 7x - 60 = 0 (x - 12) (x + 5) = 0 x = 12 or x = -5
1. 3x2+12= 3(x2+4) 2. 7x2+35x= 7x(x+5)
(x+2)(x-9)
The value of x2+7x+10 depends on the value of X. If x=1, then x2+7x+10 = 18 If x=2, then x2+7x+10 = 28 If x=3, then x2+7x+10 = 40 and so forth
=3x * * * * * The correct answer is: x2 + 7x + 12 = (x + 3)(x + 4).
x2+7x+12
x2+7x+12=0 x2+7x=-12 x+Sqaure Root of 7x= 2(SQ Root Symbol)3
-3
x2-7x+12 (x-3)(x-4)
x2 + 7x + 6 = (x + 6) (x + 1)
(x + 3)(x + 4)
Do you mean x2+7x+12? If so then it is: (x+3)(x+4)
x2 - 7x = 60 x2 - 7x - 60 = 0 (x - 12) (x + 5) = 0 x = 12 or x = -5
x2-7x-44 = (x+4)(x-11) when factored
x2+7x+12=0usually this means to factor the equation.factored this equation would be...(x+3)(x+4)
5(x2 - 7x + 12) = 5(x - 3)(x - 4)