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m2 - 4mn - 12n2

= m2 - 6mn + 2mn - 12n2

= m(m - 6n) + 2n(m - 6n)

= (m + 2n)(m - 6n)

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Related Questions

How do you factor m²-4mn-12n²?

(m + 2n)(m - 6n)


How do you factor this polynomial m2-4mn-12n2?

(m - 6n)(m + 2n)


What is 4mn m (2n 3)?

The expression (4mn(2n + 3)) represents the product of (4mn) and the sum (2n + 3). To simplify, you can distribute (4mn) to both terms inside the parentheses: (4mn \cdot 2n + 4mn \cdot 3). This results in (8mn^2 + 12mn). Thus, the final simplified expression is (8mn^2 + 12mn).


How do you solve 4mn plus 8?

4mn + 8 is an expression: it is not an equation (or inequality) and therefore there is nothing that can be solved.


What are the factors of 4mn?

They are 1, 2, 4, m, 2m, 4m, n, 2n, 4n, mn, 2mn and 4mn.


What is the simplify 7bk-9mn plus 5mn plus 2bk?

The simplified form of 7bk-9mn + 5mn + 2bk is 9bk - 4mn.


What is 4mn to the third power over 10n to the second power in simplest form?

to find the answer, you have to find the prime factorization of the two monomials 4mn^3 2*2*m*n*n*n ---------- = ------------------ 10n^2 2*5*n*n then you cross out the common numbers (so in this case: 2, n, and n) the the ones that are left are your fraction in simplest form ANSWER: 2mn ------ 5


Why do you get an odd number when you multiply two odd numbers?

Let one odd number be "2m + 1", the other odd number "2n + 1" (where "m" and "n" are integers). All odd numbers have this form. If you multiply this out, you get (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since each of the first three parts is even, the "+1" at the ends converts the result into an odd number.


WHY IS AN ODD NUMBER TIMES AN EVEN NUMBER EVEN?

Suppose m and n are integers. Then 2m+1 is an odd number and 2n is an even number.(2m + 1) * 2n = 4mn + 2n = 2*(2mn + 1). Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + 1 is an integer. Thus the product is a multiple of 2: that is, it is even.


Why is an odd number times an odd number an odd number?

Suppose m and n are integers. Then 2m + 1 and 2n +1 are odd integers.(2m + 1)*(2n + 1) = 4mn + 2m + 2n + 1 = 2*(2mn + m + n) + 1 Since m and n are integers, the closure of the set of integers under multiplication and addition implies that 2mn + m + n is an integer - say k. Then the product is 2k + 1 where k is an integer. That is, the product is an odd number.


Why does an odd number times an odd number equal an odd number?

Let's do some algebra. Assume that "m" and "n" are any integers. An even number is divisible by 2, so 2m or 2n would be even. An odd number is one that is not divisible by 2, so 2m + 1, or 2n + 1, are odd numbers.Multiply those two odd numbers together: (2m+1)(2n+1) = 4mn + 2m + 2n + 1. Since the first three parts are even, the added 1 at the end makes the result odd.


What is posterior disk osteophyte complex?

Disc osteophyte complex usually occurs as a person ages. It is a spinal condition where a spinal vertebra is afflicted by osteophytes or commonly known as bone spurs. This often results in experiencing headaches, stiff neck, and weakness in the shoulders.