(x - 3)(x2 + 3x + 9)
Factor out the GCF and get X(X2-X+1).
(x - 1)(x - 4)(x + 1)(x + 4)
(x - 1)(x4 + x3 + x2 + x + 1)
So x4 - 1 is the difference of squares, so x4 - 1 = (x2 - 1)(x2 + 1) = (x + 1)(x - 1)(x2 + 1).
x4/12 since derivative of x4/12 is 4x3/12 or x3/3
(x4 - 3)(x4 + 3)
x(x4+x3+x2+x+1)
x times x times x times x = x4
Greatest common factor of x4 and x3 is x3.
8c cubed
x times x cubed is equal to x^4, or x raised to the power of 4.
0,6x4=15x3
It is: 1(x4+4y8) and can't be factored any further
The expression a^3 + b^3 can be factored using the sum of cubes formula, which states that a^3 + b^3 = (a + b)(a^2 - ab + b^2). Therefore, a^3 + b^3 can be factored as (a + b)(a^2 - ab + b^2). This formula helps us break down the sum of two cubes into a product of binomials, simplifying the expression.
One is the only factor of 50 that is a cube.
The answer to this question is x4 easy right?!