First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.
x2 - 6x - 27 = (x-9)(x+3)
6x plus 3y minus 2x plus 5y equals 4x plus 8y.
The lines are perpendicular.
Notice that we can factor out 2x from both terms on the LH side: ... 4x2+6x=0. The greatest common factor of 4 and 6 is 2 . The greatest common factor of x2 and x ...
(6x - 1)(6x - 1)
x-8
(3x - 4)(2x^2 + 6x + 5)
(4x - 3)(2x + 3)
-((x + 2)(x - 8))
With great difficulty not knowing if 6x and 27 are plus or minus
I'm not sure this was notated correctly. As written, this is -11x plus or minus 18, which doesn't factor.
Answer is x2 -6x+14 with remainder 2
{-1,7}
First, factorising, we get: x2 - 6x - 16 = (x - 8)(x + 2). Then, (x2 - 6x - 16) / (x - 8) = x + 2.
x2 - 6x - 27 = (x-9)(x+3)
(x^2 - 2)(x - 2)(x + 2)