What about it? Factorise it?
( x2 - 121 ) = (x + 11) times (x - 11)
(x - 5)(x + 4)
factorise (x-5)(x+4)=0 Hence x= 5 or -4
It is: x(x-3) factorized
What about it? Factorise it?
x(x - 7)
13X squared + 7X + 12
( x2 - 121 ) = (x + 11) times (x - 11)
3x2 - 8x = x(3x - 8)
First, factorise both numerator and denominator: (2x - 4) / (x2 - 4) = 2(x - 2) / (x + 2)(x - 2) = 2 / (x + 2).
(x - 3)(2x - 7)
x2 + 4x = x(x + 4)
5x2 + 9x + 13 has no real factors.
Factorise it: (x + 5)(3x - 8)
X squared + 7X + 12?
(x - 5)(x + 4)