x(x - 7)
(x - 3)(2x - 7)
3x2 - 8x = x(3x - 8)
7x-x2 = x(7-x)
To factorize ( x^2 - 49 ), you can recognize it as a difference of squares. It can be expressed as ( (x - 7)(x + 7) ), since ( 49 ) is ( 7^2 ). Therefore, the complete factorization is ( (x - 7)(x + 7) ).
(x+4)(x-7)
What about it? Factorise it?
(x - 3)(2x - 7)
13X squared + 7X + 12
X2 - 4= (x + 2)(x - 2)===========
( x2 - 121 ) = (x + 11) times (x - 11)
3x2 - 8x = x(3x - 8)
x(x-7)
7x-x2 = x(7-x)
To factorize ( x^2 - 49 ), you can recognize it as a difference of squares. It can be expressed as ( (x - 7)(x + 7) ), since ( 49 ) is ( 7^2 ). Therefore, the complete factorization is ( (x - 7)(x + 7) ).
5x2 + 9x + 13 has no real factors.
It is (x+6)(x+7) when factored
(x+4)(x-7)