a2+b2=c2
9+25=c2
34=c2
then find the square root of 34
I think you have not asked the question correctly.I guess you meant that the sides of the triangle are 3, 4 and 5. Similarly you have given no indication of which angle is opposite which side.A 3, 4, 5 triangle is a right angle triangle (5 is the hypotenuse).Thus depending where angle B is, its sine will be:If B is opposite the side of length 3, sin B = 4/5If B is opposite the side of length 4, sin B = 3/5If B is opposite the side of length 5, sin B = 5/5 = 1; alternatively ∠B = 90° and sin B = sin 90° = 1
If -5 + b = 3, then b = 8.
It is B
x= 2*3(5+7) always do whats in parenthesis first. 5+7=12 and then 2*3=6 so it would give you 6*12=72
What is an angle in the triangle
the answer would be 5.you would use the Pythagorean Theorum.a(squared)+b(squared)=c(squared)3*3=9 4*4=169+16=25then you would find the square root of 25, which if 5 ;D
I think you have not asked the question correctly.I guess you meant that the sides of the triangle are 3, 4 and 5. Similarly you have given no indication of which angle is opposite which side.A 3, 4, 5 triangle is a right angle triangle (5 is the hypotenuse).Thus depending where angle B is, its sine will be:If B is opposite the side of length 3, sin B = 4/5If B is opposite the side of length 4, sin B = 3/5If B is opposite the side of length 5, sin B = 5/5 = 1; alternatively ∠B = 90° and sin B = sin 90° = 1
a = 3/sqrt(2)*i + 3/sqrt(2)*jb = 5ja.b = |a|*|b|*cos(q)= 3*5*cos(45) = 15/sqrt(2)
That's a right, scalene triangle. 3 , 4 and 5 are called triplets where 'a'=3, 'b'=4 and 'c'=5
if you meant to write the problem as "3b + 5 = 29", then this is how to solve: 3b + 5 = 29 - 5 - 5 subtract 5 from each side 3b = 24 simplify b = 8 divide each side by 3 to get b by itself
To find the hypotenuse with angle a and side b, we use the identity below:cos(a) = b/cWe have a and b, and to find c, we multiply both sides by c and divide both sides by cos(a):c = b/cos(a)c = 5/cos(30)c = 32.41460617mm
The length of side A squared plus the length of side B sqaured equals the missing side of the triangle squared. So i.e. if side A is 4 and side B is 3 then 4x4 which is 16 plus 3x3 which is 9 equals 25 and the square root of 25 equals 5. So in conclusion the missing side equals 5.
3b - 3 - 4b = 5Combine the 3b and the -4b :-1b - 3 = 5 Add 3 to each side of the equation:-1b = 8 Multiply each side by -1 : b = -8
A = 5 + 3*b To solve for b, rewrite as b = (A - 5) / 3
If -5 + b = 3, then b = 8.
It is B
Suppose a is one side, b is the other side, and c is the last side. If a+b > c, b+c > a, c+a > b, you can construct this traingle. Or in simpler terms, any two side lengths'sum has to be bigger than the third. E.G. If one side was 2, one side was 5, and the other side was 2, than you aren't able to construct the traingle because 2+2 isn't bigger than 5. BUT If one side was 2, the other side was 2, and the last was 3, than you could because 2+2>3, 3+2 > 2, and 2+3 > 2.