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Using exact values find the numerical value of sin 30 degrees cos 240 degrees plus sin 210 degrees sin 300 degrees?
SQRT(3)/4 - 1/4
What is the value of sin of 62 degrees?
It is: sin(62) = 0.8829475929.
What is the value of sin 40 degrees?
It is:- sin(40) = 0.6427876097
X is acute and sin x equals cos x Find cos?
x = 45 degrees sin(x) = cos(x) = 1/2 sqrt(2)
What is the sin of 42 degrees rounded to the nearest hundredth?
42.00
Find sin 26.1 degrees?
The answer is 42.
Using exact values find the numerical value of sin 30 degrees cos 240 degrees plus sin 210 degrees sin 300 degrees?
SQRT(3)/4 - 1/4
Sine of 10 degrees x 12 equals?
Sin(10)*12 = 12*sin(10) = 12*0.1736 = 2.0838, approx.
What is the sine of 10 degrees?
sin 10° = 0.17364817766693 Source: http://calculator3.sdsu.edu/calculator3.php
If angle A is 60 degrees angle B is 45 degrees angle C is 75 degrees and the length of side AC is 10 units then what is the length of side AB?
This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)
Find the value of sin 300 degrees?
sin 300 = -sin 60 = -sqrt(3)/2 you can get this because using the unit circle.
What is the sin 29 equals x divided by 10?
2.9
Find out reasons sin is prevalent in our present days?
= Find out 10 reasons sin is prevalent in our present days? =
What is sin 57 degrees?
sin 57 degrees
What is sin 97 degrees?
all sin is sin97 degrees Fahrenheit = 36.1 degrees Celsius
Sin equals 0.9?
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
What is the refractive index of a medium when the light strikes the medium after traveling through air at an angle of 23.3 degrees and the refracted angle is 14.6 degrees?
To find the refractive index of the medium, we can use Snell's Law, which states that ( n_1 \sin(\theta_1) = n_2 \sin(\theta_2) ). Here, ( n_1 ) (the refractive index of air) is approximately 1, ( \theta_1 ) is 23.3 degrees, and ( \theta_2 ) is 14.6 degrees. Rearranging the equation gives us ( n_2 = \frac{\sin(\theta_1)}{\sin(\theta_2)} ). Calculating this, we find ( n_2 \approx \frac{\sin(23.3^\circ)}{\sin(14.6^\circ)} \approx 1.47 ).
