It is 60.
1/6 n(n+1)(n+2)
You first have to figure out some rule for the sequence. This can be quite tricky.
i dont get it
To find the nth term in a quadratic sequence, we first need to determine the pattern. In this case, the difference between consecutive terms is increasing by 3, 5, 7, 9, and so on. This indicates a quadratic sequence. To find the 9th term, we need to use the formula for the nth term of a quadratic sequence, which is given by: Tn = an^2 + bn + c. By plugging in n=9 and solving for the 9th term, we can find that the 9th term in this quadratic sequence is 74.
Oh, what a happy little question! If the 20th term in a sequence is 50, that means we're adding the same amount each time. To find the 21st term, we just need to keep adding that same amount. So, if the 20th term is 50, the 21st term would be 50 plus that special amount. Just keep on adding and you'll find your answer, like painting a beautiful little tree in the sunset.
It is 60.
First, you must find the difference between the numbers, for example if the numbers were 3, 5, 7, 9, 11 then it would be 2. All you have to do is find out the difference between 2 and the first number, which happens to be 3. So 3-2 equals 1.so the equation would be2n+1you always use n for the nth sequence term
1, 3, 6, 10, 15 ,21 The nth term for the sequence (where you replace n with the term you want to find) is: (n(n+1))/2
what term is formed by multiplying a term in a sequence by a fixed number to find the next term
a + 99d where 'a' is the first term of the sequence and 'd' is the common difference.
The 90th term of the arithmetic sequence is 461
1/6 n(n+1)(n+2)
The sequence is Un = 19 - 3n so the 20th term is 19 - 3*20 = 19 - 60 = -41
The sequence given is an arithmetic sequence where each term is the sum of the previous term and a constant difference. The constant difference in this sequence is increasing by 1 each time, starting with 2. To find the 100th term, we can use the formula for the nth term of an arithmetic sequence: ( a_n = a_1 + (n-1)d ), where ( a_n ) is the nth term, ( a_1 ) is the first term, ( n ) is the term number, and ( d ) is the common difference. Plugging in the values, we get ( a_{100} = 1 + (100-1)2 = 1 + 99*2 = 1 + 198 = 199 ). Therefore, the 100th term in the sequence is 199.
If the nth term is 8 -2n then the 1st four terms are 6, 4, 2, 0 and -32 is the 20th term number
you must find the pattern of the sequence in order to find the next 50 terms using that pattern and the first part of the sequence given