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Q: How do you find the area of a triangle whose vertices have the coordinates ( -1 -1) (-13) and (5 -1)?

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Select any one of the vertices and draw all the diagonals from that vertex. This will divide the polygon (with n sides) into n-2 triangles. Use the coordinates of the vertices of each triangle to calculate its area, and then add the areas of these triangles together.

The area of triangle is : 80.0

The area is calculated easily using the determinant of the matrix of coordinates, or Heron's formula and is 15 square units.

The base of the right-angled triangle = 4 units The height = 6 units The area = 0.5 * base * height = 12 square units =========================

Assuming that these are coordinates of the vertices, the area is 6 square units.

The area of triangle is : 100.0

It is an isosceles triangle with a perimeter of 26+(4 times square root of 13) linear units and an area of 78 square units

The area of triangle is : 90.0

By plotting the given vertices and then joining them together on the Cartesian plane the shape of a isosceles triangle will be formed with an area of 78 square units.

The area of triangle is : 100.0

The area of triangle is : 60.0

84.87

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