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You need to think of that equation in terms of the classic definition of a circle:
(x - a)2 + (y - b)2 = r2
where a and b are the center of the circle, x and y are any point on it's circumference, and r is it's radius.
In the case of the circle you're looking at:
x2 + y2 = 16
You can re-express it like this:
(x - 0)2 + (y - 0)2 = 42
So that circle has a center at the point (0, 0), and a radius of 4.
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What is the equation for a circle with a center of (3 0) and a radius of 12?
(x-3)2+y2=144
This circle is centered at the origin and the length of its radius is 4 What is the equation of the circle?
x2 + y2= 16
What is the length of the circle radius if the circle is x2 plus y2 equals 1?
The center of the circle is at (0, 0) and its radius is the square root of 1 which is 1
The equation of the inner circle is x2 plus y2 equals 4 the radius of the outer circle is four times the radius of the inner circle write the equation of the outer circle?
The inner circle is x2 + y2 = 4. The radius of the inner circle is the square root of 4, which is 2. To find the radius of the outer circle, multiply 2 times 4. The radius of the outer circle is 8. Square 8 (82 or 8 x 8) to find the number to put into the equation of the outer circle. This is 64. The equation for the outer circle is x2 + y2 = 64.
What is the equation of a circle whose center is at the origin and whose radius is 10?
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
