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x2+y2+4x+2y+3=0

(x+2)2 + (Y+2.5)2 = 3

This is the equation of circle with center at (-2,-2.5) with radius 3.5

Q: Find the center and radius of the circle with this equation x2 plus y2 plus x equals 0?

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That's the equation of a circle with its center at the origin and a radius of 8.

If that equals 16 then the radius is 4

You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)

The equation of a circle can be written in the form (x-h)2 + (y - k)2 = r2, where r is the radius, and (h,k) is the center. So for your example, the equation would be: (x- 5)2 + (y - 3)2 = 72

If you mean: (x+9)^2 + (y+5)^2 = 64 Then the center of the circle is at (-9,-5) and the radius is 8

Related questions

That's the equation of a circle with its center at the origin and a radius of 8.

Centre = (0,0), the origin; radius = 11

It is the equation of a circle with radius of 6 and its center at the origin.

Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2

Radius = 1111

Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..

The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2

depends on the equation.

The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100

Center of circle: (6, 8) Radius of circle: 3

Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.

If that equals 16 then the radius is 4