There is not sufficient information.
Any equation of the form y = ax3 will intercept the x-axis only at (0,0), for any non-zero value of a. This is a triple root of the equation.
Furthermore, consider any equation of the form y = (x-p)*Q(x) where Q(x) is any quadratic function of x without real roots.
This is the equation of a cubic which has only one x-intercept: at (p,0).
The graph of an equation has a slope and intercept.[ 13x - 11y - 12 ] is not an equation, and has no graph,until you say that it's equal to something.
The y-intercept of a linear equation is the point where the graph of the line represented by that equation crosses the y-axis.
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.
no the graph will be written in slope intercept form or y=mx+b
First write it in the "slope-intercept" form : y = mx + c Then the y-intercept is (0, c)
Without an equality sign the given term can't be considered to be an equation.
There is no y-intercept or slope for this given equation, because its graph is a vertical line perpendicular to the x-axis.
Solve f(x) =0 or y = 0 (depending on how the equation is given).
Without an equality sign the given term can't be considered to be an equation.
You can graph a linear equation slope intercept by solving the equation and plugging in the numbers : y=mx+b
The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.
The x intercept is at (84, 0) and the y intercept is at (0, 112) and so with a line join the points together which then will form a graph for the given equation.
To find the y-intercept from a graph - look at where the graph of the line intersects the y-axis. The point at where the graph of the line crosses the y-axis will be the y-intercept with the coordinates of (0,y) The point at which the line cuts the y – axis is called as y – intercept.You can locate the point by seeing the graph.Note:If you are given a linear equation say ax + by + c = 0Now if we plug x = 0 in the given equation we will get the y – intercept.y = -c/bIf the given equation is of the form y = mx + bb is the y – intercept of the line. Source: www.icoachmath.com
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yx-3 is not an equation, and it has no graph.
The graph of an equation has a slope and intercept.[ 13x - 11y - 12 ] is not an equation, and has no graph,until you say that it's equal to something.
The intercept of a graph is the point where is crosses one of the coordinate axes. The x intercept is where it crosses the x axis, the y intercept where it crosses the y axis. If the graph is given as y equals a function of x, it is usually easier to find the y intercept, because that is where x is 0. You just plug in 0 for x and evaluate. To find the x intercept, you plug in 0 for y and then you have to solve an equation for x. This is fairly easy if it is a linear equation (the graph is a straight line), somewhat harder for a quadratic (a parabola). But anyway you only asked for a definition, and I have given it.