To find the y-intercept from a graph - look at where the graph of the line intersects the y-axis. The point at where the graph of the line crosses the y-axis will be the y-intercept with the coordinates of (0,y) The point at which the line cuts the y – axis is called as y – intercept.
You can locate the point by seeing the graph.
Note:
If you are given a linear equation say ax + by + c = 0
Now if we plug x = 0 in the given equation we will get the y – intercept.
y = -c/b
If the given equation is of the form y = mx + b
b is the y – intercept of the line. Source: www.icoachmath.com
You can either measure or estimate the coordinates visually from the graph, or solve the equation underlying the graph.
2x plus y = -3 (subtract 2x from both sides) y = -2x - 3 slope = -2 y-intercept = -3
12
Select any value for one of the variables in the graph and solve the equation to get the other variable.
y = - x2 +6x - 5.5
A linear function is called "linear" because it represents a straight line. To graph a linear function, find two points that satisify that function, plot them, and then draw a straight line between them.
3s=2t can also be written as 3y=2x or 3x=2y. Either way, it is linear. To find out if it is linear, simply graph it. If you can draw a completely vertical line through any point of the graph without intersecting more than one point of the graph, then it is linear. This equation (3s=2t), it is linear.
No
In general, it is very difficult. Even if a graph looks like a straight line over the domain there is no guarantee that the underlying equation makes the equation non-linear as you move away from the visible domain. A typical example, from school physics, concerns Hooke's law. The extension of a length of wire under different strains follows a linear relationship. Until the strain reaches a critical level and then the relationship goes all haywire. Looking at the graph below that critical level, the equation would be a straightforward linear one. But that is true only as far as it goes.
you have to look at the graph. find where the line crosses the x and y axis' and there is your solutions.
By the substitution method By the elimination method By plotting them on a graph
Linear Programming is used for determining a way to find the best solution or outcome for a given mathematical model represented as a linear relationship.
DFS, BFS
To find acceleration from a speed-time graph, you need to calculate the slope of the speed-time graph. The slope at any point on the speed-time graph represents the acceleration at that specific time. If the speed-time graph is linear, then the acceleration will be constant. If the speed-time graph is curved, you can find the acceleration by calculating the slope of the tangent line at a specific point.
You cannot. Or rather, you should not. You do not know if the relationship is linear or something else. A scatter graph is the best way to establish the nature of the relationship. For example, the correlation between x and y, when y = x2 between, say, -4 and +4 is zero (because of symmetry). That would lead you to conclude that there was no relationship. You could not be more incorrect!
There are many ways to graph linear equations. One way that will always work it to pick some points, 3 is plenty. Pick and x value, plug it in and then find the y value. You will obtain a set or ordered pairs. Graph these and connect the dots. Voila------------- a line!
Follow the graph's positive slope (across the first quadrant) until the graph is no longer linear. The yield strength is determined to be the last point (with concern given to the stress value) on the linear section. After this point the graph is irregular because the material has failed to a point of no return and can no longer handle the load (stress).