So, you divide the base by 2. Then, you divide the area by that answer and you'll find the height.
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.
area of a triangle is given by the formula 1/2 * base *height therefore the area of the following is 1440 unit square
Area = 0.5*base*height Note that the given dimensions would not form a triangle
The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.The area of a triangle is (1/2) base times height; the height must be perpendicular to the base.
The formula for the area of a triangle is ½ x base x height. We are given that the base = 13 cm and the height = 8 cm. Thus, the area of the triangle = ½ x 13 cm x 8 cm = 52 cm.
The relation between the height of a triangle, its base and its area is given by: Area = 0.5 * Base * Height Therefore, we have: Height = (2 * Area)/ Base.
Divide the area by height then you get the base.
area of a triangle = 1/2 base x height ie times the area by two then divide by the base = height
Area = 1/2*Base*Height so Base = 2*Area/Height
The height has not been given but the area of the triangle is: 0.5*height*base
If the shape in question is a triangle, then Area = 0.5 * Base * Height So Height = 2 * Area / Base
Of a square? (area/height=base) Of a triangle? ({area/height}/2=base) Or of some other shape?
That will depend on the height of the triangle which has not been given. Base = (84*2)/height
Multiply the area by 2 and then divide the result by its height which will give you the base.
area of a triangle is given by the formula 1/2 * base *height therefore the area of the following is 1440 unit square
Area of a triangle = base * height / 2 Therefore the base = Area * 2 / height
Divide the area by half the base.