It is very unlikely for a right angle triangle to be isosceles, however it is possible if the angles are 90, 45, and 45 degrees. It does not matter if the triangle is isosceles, this method works for all right triangles. The following formula is your answer, when h=hypotenuse, and a and b are other two sides. a2 + b2 = h2
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Use the sine rule to work out one of the sides. (a/sina = b/sinb = c/sinc) Then as it is an isosceles triangle the perpendicular dropped from the apex will (a) bisect the base and (b) form a right angle with the base. Now you know one side and the hypotenuse of a right-angled triangle and you use Pythagoras (a2 + b2 = c2) to solve the 'other' side of that, which is the height of the isosceles triangle.
An isosceles triangle is in effect two right angled triangles joined together and in this case they have bases of 5 units and heights of 2 units so use Pythagoras' theorem to find the hypotenuse which will be the length of one of the equal legs of the isosceles triangle:- 52+22 = 29 and the square of this is about 5.385164807 or 5.385 to 3 dp
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First you half all the sides, so 4cm, them you multiply by pi, giving the radius as 12pi, or 12.56637061
That's not enough information to solve the problem.