An isosceles triangle is in effect two right angled triangles joined together and in this case they have bases of 5 units and heights of 2 units so use Pythagoras' theorem to find the hypotenuse which will be the length of one of the equal legs of the isosceles triangle:-
52+22 = 29 and the square of this is about 5.385164807 or 5.385 to 3 dp
Yes if the isosceles triangle is a right isosceles triangle because that leg opposite the hypotenuse is the height
Any length greater than 3 inches.
Find this using the Pythagorean theorem (a=(1/2 * 8) b=the altitude c = 6).
the area of a right angled triangle is 30sqcm one leg is 6cm what is the length of the other one
56.08921465 or about 56 square units Worked out by using Pythagoras' theorem and area = 1/2*base*height.
The base.
What is the length of a leg of an isosceles right triangle if it is area is 72 square inches?
If the base of an isosceles triangle is 11 and its perimeter is 39, then it has a height of 12.87.
Yes if the isosceles triangle is a right isosceles triangle because that leg opposite the hypotenuse is the height
square root of 28
It is one of the two equivalent sides on the isosceles triangle.
Square root of 45.
The isosceles triangle wasn't invented. The word isosceles is from Late Latin and from Greek isoskelēs, from iso- + skelos leg.
The word "isosceles" comes from Greek roots and means "equal leg." An isosceles triangle has two sides of equal length.
Either of the two congruent sides of an isosceles triangle. See attached link for a picture.
Let the base length be x:- If: 2(0.5x+9)+x = 146 => x+18+x = 146 => 2x = 146-18 => x = 64 Therefore the isosceles triangle has 2 equal sides of 41 inches and a base of 64 inches Check: 41+41+64 = 146 inches
The area of a triangle is one half base times height. In the case of a right triangle, the base is one leg and the height is the other leg. (The two legs being separated by the right angle.)