it cannot be solved
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Actually, you can. Suppose, as an example, that the rectangle's area and perimeter are 6 and 10 respectively. Let therectangles length and width be represented by L and W respectively. Then
LW = 6 (a) and
2 ( L + W ) = 10 (b)
Let me rearrange (b) to obtain an expression for W: W = 5 - L.
Now let me substitute this expression for W in (a): L ( 5 - L ) = 6.
This is a quadratic equation that one can solve for L. Let me do it by factoring,
L^2 - 5 L + 6 = 0 = ( L - 2 ) ( L - 3 )
This implies that L=2 or L=3. With L=2, W=3; with L=3, W=2. Put simply the rectangle's length and width are 3 and 2 respectively.
Length = (Perimeter - twice width) / 2
The perimeter of a rectangle is given by:P = 2l + 2w, where P is the perimeter of the rectangle, l is the length of the rectangle, and w is the width of the rectangle.P = 2(15) + 2(10) = 50 meters.
perimeter 24 so length + width half of that ie 12. Length 3 times width must be 9 and width 3.
108 feet is the perimeter of a rectangle with a length of 50 feet and a width of 4 feet.
The width of the rectangle would be 32.5 meters.
Length = (Perimeter - twice width) / 2
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
by appying 2l+2w
Perimeter = 2*(L + W).
Perimeter is Length + width x 2 or Length + length + width + width. This is perimeter for any shape including a rectangle. Perimeter of a rectangle is all sides added together for a rectangle.
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
The perimeter of a rectangle whose length is 5cm wit a width of 6cm is 22cm
Multiply length by width
The length of the rectangle is 18cm. The width of the rectangle is 9cm.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.