1. Chord length and rise:
Three points determine a circle, so if you measure the distance
between two points on the circle, then go perpendicular to that line
from the center of the line and measure the distance to the third
point on the circle, you can calculate the radius. If the first
distance is 2*a (divide it by 2 to get a), and the second distance is
b, the rise of the arc
2*a
Then the radius is r = (a^2 + b^2)/(2b). - Pythagoras Theorem
I calculated this by putting the intersection of the chord and line at
(0,0) and plotting your three points as,
(-a, 0), (a, 0), and (0, b).
And then plugging those into the general form of the equation for a
circle, namely
(x - h)^2 + (y - k)^2 = r^2.
I got h = 0, k = (b^2 - a^2)/(2b), and r = (a^2 + b^2)/(2b).
You could use this technique. If you don't have the length
a (or 2a) but you have the length of the curved side (arc length, say c)
(This is what you asked - Radius from Arc length and rise)
then you have a much harder equation to solve for r:
2br = (sin [c/(2r)])^2 + b^2.
But be warned that these computations assume that your curve is a
portion of a circle. If it is some other curve, then there is no radius.
The radius of a cylinder given only the height could be anything you like.
In a right angles triangle the sides are named the hypotenuse (the side opposite the right angle) and the other two sides are called the adjacent and the opposite sides. 1) The sine of an angle = length of the opposite side ÷ length of the hypotenuse. 2) The cosine of an angle = length of the adjacent side ÷ length of the hypotenuse. Using 1) The length of the hypotenuse = length of the opposite side ÷ the sine of the angle. Using tables or a calculator obtain the sine of the angle and divide this into the length of the opposite side. The result will be the length of the hypotenuse.
The radius of a circumference is half of the diameter. To find the radius of a circumference with a length of 64cm, you need to divide the circumference by 2π (since the formula for the circumference of a circle is C = 2πr). So, the radius would be 64cm / (2π) ≈ 10.19 cm.
The perimeter of a plane figure is the length of its boundary. Thus the perimeter of a square of length L is 4L. So the perimeter of a square of length 4 is 4 x 4 = 16 (4 + 4 + 4 + 4 = 16). The perimeter of a circle is the length of its circumference.If you are asking for the circumference of the circle circumscribed and inscribed in this square, their circumference will be:First, we need to find the measure length of their radius. We know that the diagonals of the square form 4 congruent isosceles triangles with the base length equal to the length of the square, and length side equal one half of the diagonal length ( the diagonals of a square are equal in length and bisect each other (and bisect also the angle of the square ), so the center of the circumscribed circle of the square will be the point of their intersection, and its radius will be the one half of the diagonal of the square). We can find the diagonal length by using the Pythagorean theorem. So from the right trianglewhich is formed by drawing one of the diagonals, we find the length of the diagonal which is also the hypotenuse of this right triangle, and which is equal to square root of[2(4^2)]. So the length of the diagonal is equal 4(square root of 2), and its half is 2(square root of 2), which is the length of the radius of the circumscribed circle. So its circumference is equal to (2)(pi)(2(square root of 2)) = 4(square root of 2)pi.Now, we need to know what is the length of the radius of the inscribed circle, and what is this radius. Let's look at the one of the fourth triangles that are formed by drawing the two diagonals of the square. If we draw the perpendicular from the intersection of the diagonals to the side of the square, this perpendicular is the median of the side of the square and also the altitude of this isosceles triangle. Let's find the measure of its length. Again we can use the Pythagorean theorem. So this measure is equal to the square root of [(2(square root of 2))^2] - 2^2] which is equal to 2. If we extend this perpendicular to the side of the triangle and draw another perpendicular from the point of the intersection of the diagonals to the other sides of the square, their length will be also 2. Since they have the same distance from the point of the intersection of the diagonals, we can say that their length is the length of the radius of the inscribed circle, and the point of the intersection of the diagonals is also its center. So the measure of length of the radius is 2, and the circumference of the inscribed circle is (2)(pi)(r) = (2)(pi)(2) = 4pi.As a result, we can say that the point of the intersection of the diagonals of a square is the center of its inscribed and circumscribed circle, and the perpendicular lines drawing from this point to the sides of the square bisect each other. (These perpendiculars are parallel and equal in length to the square length, because we know that two lines that are perpendicular respectively to the other two parallel lines, are equal in length and parallel between them). We also can say that in an isosceles triangle with 45 degrees base angle, the median is not only also an altitude, but its length is one half of the length of the base.
i can
You cannot.
Just did this in my trig class yesterday. Arc length = radius * theta(radians) Circumference of Earth = radius of earth * 2pi Note: The arc length is the circumference of the Earth only in this case because theta is equal to 2pi.
Length = angle˚/360˚ x 2∏r
radius = diameter/2 radius = circumference/2*pi
Square Root
you have a triangle formed by the radius on 2 and the chord on the other. the angle in that triangle that is opposite the chord, find its measure in radians take that measure (in radians) and multiply it by the radius to get the arc length
Since the formula for the area of a circle is pi times the radius squared and the formula for the circumference is two times pi times the radius, you would find the circumference by first dividing by pi. This would give you the radius squared. Find the square root of this value. This will give you the length of the radius. Take this length and multiply it by two times pi.
If you have the arc length:where:L is the arc length.R is the radius of the circle of which the sector is part.
The radius is the distance from the center of the circle to its edge. No matter how you draw this radius, it is one value of one length only, for any given circle.
You can multiply a radius in any unit of length that you like. It all depends on the application
The radius is half the diameter.
By using this formula: V = radius2 x Pi x height