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distance travelled in x direction divided by distance travelled in y direction

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Actually that's wrong, it should be distance y / distance x, essentially the slope is the hypotenuse of a right angle triangle,

Draw the graph v = 0.5 t for values of t between 0 and 5 , step 1 along the x axis, fill in values for v up the y axis, if t = time and v = velocity, the slope of the graph represents velocity change / time, which is acceleration.

Start on the slope where t = 2 seconds, draw a line to the right to 3 seconds, draw up to intersect the slope, the length of this vertical line represents velocity change ( = 0.5 m/s) , the first line represents time ( = 1 second), divide 0.5 by 1

= 0.5 ((m / s) / s) which is the acceleration derived from the velocity/ time graph by calculating the slope of the graph.

note:

if its a mathematically produced line , then differential calculus can be used to calculate the slope , or integral calculus can be used to calculate the area under the curve between two points, which in this case would represent distance travelled.

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Q: How do you find the slope of a graph that has a straight line?
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