distance travelled in x direction divided by distance travelled in y direction
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Actually that's wrong, it should be distance y / distance x, essentially the slope is the hypotenuse of a right angle triangle,
Draw the graph v = 0.5 t for values of t between 0 and 5 , step 1 along the x axis, fill in values for v up the y axis, if t = time and v = velocity, the slope of the graph represents velocity change / time, which is acceleration.
Start on the slope where t = 2 seconds, draw a line to the right to 3 seconds, draw up to intersect the slope, the length of this vertical line represents velocity change ( = 0.5 m/s) , the first line represents time ( = 1 second), divide 0.5 by 1
= 0.5 ((m / s) / s) which is the acceleration derived from the velocity/ time graph by calculating the slope of the graph.
note:
if its a mathematically produced line , then differential calculus can be used to calculate the slope , or integral calculus can be used to calculate the area under the curve between two points, which in this case would represent distance travelled.
The graph of the equationy = 2x + any numberis a straight line with a slope of 2.
A straight line graph with negative slope slants downward from left to right.
find the constant of variation and the slope of the given line from the graph of y=2.5x
The graph of the equation is a straight line. 'm' is its slope. 'b' is its y-intercept
The graph of [ y = -3x ] is a straight line, through the origin, with slope of -3 .
A line. The derivative of a function is its slope. If the slope is a constant then the graph is a line.
The graph of the equationy = 2x + any numberis a straight line with a slope of 2.
A straight line graph with negative slope slants downward from left to right.
The graph of [ y = 4x + 2 ] is a straight line with a slope of 4.Any line with a slope of 4 is parallel to that one, and any line parallel to that one has a slope of 4.
The slope of each point on the line on the graph is the rate of change at that point. If the graph is a straight line, then its slope is constant. If the graph is a curved line, then its slope changes.
It is the gradient (slope) of the line.
It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.It is a straight line through the origin, with a positive slope.
The acceleration of the ball can be estimated by calculating the slope of the velocity versus time graph. If the graph is a straight line, the slope represents the acceleration. The steeper the slope, the greater the acceleration. If the graph is curved, the instantaneous acceleration can be estimated by finding the slope of the tangent line at a specific point on the curve.
If velocity is constant, the slope of the graph on a position vs. time graph will be a straight line. The slope of this line will represent the constant velocity of the object.
A straight line with a positive slope on a position-time graph is the graph of an object that's moving in a straight line with constant speed.
Slope of a straight line on a Cartesian coordinated graph is 'rise over run' = y2-y1/x2-x1 = change in 'y'/change in 'x'
Slope of a straight line on a Cartesian coordinated graph is 'rise over run' = y2-y1/x2-x1 = change in 'y'/change in 'x'