If it is the frustum of a pyramid: The volume of a pyramid (with a square base) is: Length_of_base * Width_of_base * Height * 1/3 To get the volume of the frustum, subtract the volume of the top part (also a pyramid) from the full volume.
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frustum of a cone
the formula is
(h*pi)/3*(r1^2+r2^2+r1*r2)
this is where h = height r1= top radius r2=bottom radius
A frustum. Specifically, a frustum of a triangular pyramid -- as one could also have a frustum of a cone, square pyramid, etc.
You find the length and height of the shape, them you find the volume
You cannot find the volume of a square. You can find the volume of a cube, which is finding the length of one edge of the cube and taking that to the third power, or cubing it.
use the formula 4/3*π*radius3 to find the volume of a sphere.
The volume of a sphere is 4 / 3 * pi * r3
A large cone has a greater volume than a small frustum while a small cone has a smaller volume than a large frustum
A cone can have a greater volume than its frustum, but it depends on the dimensions of both the cone and the frustum. The volume of a cone is calculated using the formula ( V = \frac{1}{3} \pi r^2 h ), while the volume of a frustum is given by ( V = \frac{1}{3} \pi h (R^2 + Rr + r^2) ), where ( R ) and ( r ) are the radii of the two bases of the frustum. If the frustum is formed by cutting off the top of the cone, its volume will always be less than that of the original cone.
Yes, it must because a frustum is only a part of a cone.
i have an answer for both a frustum of a pyramid and a frustum of a cone which do you need frustum of a cone just give both of them
Yes
To calculate the weight of a frustum, first determine its volume using the formula: ( V = \frac{1}{3} \pi h (R^2 + r^2 + Rr) ), where ( R ) is the radius of the larger base, ( r ) is the radius of the smaller base, and ( h ) is the height. Once you have the volume, multiply it by the material's density (( \text{Weight} = \text{Volume} \times \text{Density} )) to find the weight of the frustum.
You can find some of these solutions online. An example would be the volume of frustum or a similar problem.
first tell me the formula
Most likely, a frustum of a sphere.Most likely, a frustum of a sphere.Most likely, a frustum of a sphere.Most likely, a frustum of a sphere.
There is no frustum of a cone. There is a frustum, which is a cone with the top cut off parallel to the ground.
If the sides of the top and base of the pyramidal frustum are 3 and 8 metres units then the radius of the cylinder is 3.2081 metres.
The length of a solid conical frustum is the distance from the top to the bottom of the frustum along its central axis.