Solve the quadratic equation.
If y = ax^2+bx+c then the intercepts are
x = [-b +/- sqrt(b^2 - 4ac)]/(2a).
The solutions are real if and only if b^2 >= 4ac
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Y = X2 ===== The graph of this parabola is crossed only at a point and once by a vertical line, so it is a function. Passes the vertical line test.
If a vertical line passes through the supposed function at only one spot then you have a function.
You need more than one tangent to find the equation of a parabola.
The given equation is not that of a parabola.
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.