Solve the quadratic equation.
If y = ax^2+bx+c then the intercepts are
x = [-b +/- sqrt(b^2 - 4ac)]/(2a).
The solutions are real if and only if b^2 >= 4ac
Y = X2 ===== The graph of this parabola is crossed only at a point and once by a vertical line, so it is a function. Passes the vertical line test.
If a vertical line passes through the supposed function at only one spot then you have a function.
You need more than one tangent to find the equation of a parabola.
The given equation is not that of a parabola.
Standard notation for a quadratic function: y= ax2 + bx + c which forms a parabola, a is positive , minimum value (parabola opens upwards on an x-y graph) a is negative, maximum value (parabola opens downward) See related link.
A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.A parabola has no endpoints: it extends to infinity.
Yes, it is.
A 'Parabola'
Y = X2 ===== The graph of this parabola is crossed only at a point and once by a vertical line, so it is a function. Passes the vertical line test.
A parabola
The parabola
It is a function because for every point on the horizontal axis, the parabola identified one and only one point in the vertical direction.
It is a square root mapping. This is not a function since it is a one-to-many mapping.
Any equation where variable a = some multiple of variable b2 + constant will graph a parabola.
The point on the parabola where the maximum area occurs is at the vertex of the parabola. This is because the vertex represents the maximum or minimum point of a parabolic function.
If a vertical line passes through the supposed function at only one spot then you have a function.
the graph of a quadratic function is a parabola. hope this helps xP