A tangent refers to the way in which a curve is measured. The amount of deviation from the segment line is measures, then a formula applied to find the tangent.
You need more than one tangent to find the equation of a parabola.
Find the slope of the tangent to the graph at the point of interest.
You can find a vertex wherever two lines (or line segments) meet.
Assuming you know the angle of ascension, and the base, you can calculate the height by recalling that tangent theta is height over base. Simple algebra from there: height is tangent theta times base.
Say you are given a function and an x value.(1) First find the y coordinate that corresponds to that x value by plugging x into the function and simplifying to find y = some #. Now you have a point (x, y) that is not only on the function, but also on the tangent line.(2) Take the derivative of the function.(3) If the derivative still has xs in it, plug in the x value you were given and simplify. This should give you an actual number--the slope of the tangent line.(4) From steps 1 and 3, you now have a point on the tangent line and the slope of the tangent line. Use these two things to write the equation for the tangent line in y=mx+b form (m is the sope, plug in the point you found, solve for b, then rewrite the equation replacing m and b but leaving in x and y).
You find the tangent to the curve at the point of interest and then find the slope of the tangent.
a tangent is a line that touches the circle at only ONE point
Cotangent is ' 1/tangent' or ' Cosine / Sine'.
budosnp
You need more than one tangent to find the equation of a parabola.
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Sine = -0.5 Cosine = -0.866 Tangent = 0.577
Take the inverse tangent -- tan-1(opposite side/adjacent side)
Use the four-step process to find the slope of the tangent line to the graph of the given function at any point.
Take the derivative of the function.
You cannot.
The question is suppose to read: Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8