Each factor will contribute a zero. f(x) = Ax^2 + Bx + C will take the form of something like f(x) = (x-r1)(x-r2) when you factor it. Now the zeros are the values of x for which f(x) = 0. You know 0 times anything is zero, so consider one factor at a time. (x-r1) will equal zero when x = r1, therefore r1 is a "zero" (or "root") of f(x). Incidentally, f(x) = 0 when x = r1 because 0*(x-r2) = 0 for any value of r2.
To find the second "zero" find the value of x that makes (x-r2) equal zero.
If f(x) = (x+2)(x+3) then the zeros are -2 and -3, because f(-2) = 0 and f(-3) = 0.
So if you can factor a function, you can easily find its zeros. The challenge is actually factoring the function.
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The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
by synthetic division and quadratic equation
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
You could try setting the function equal to zero, and finding all the solutions of the equation. Just a suggestion.
The Independent Factoring Brokers Association is headquartered in the United Kingdom. There is no regulation regarding factoring brokers thus anyone can call themselves a factoring broker and provide advice.