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One way is : 1 + (2 + 6) * 7 = 1 + 8 * 7 = 1 + 56 = 57

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Q: How do you get 57 out of 1 2 6 and 7?
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How do you algebraically solve these simultaneous equations - 3x plus 2y equals 7 and y equals x2 - 2x plus 3?

To solve:-3x + 2y = 7y = x2 - 2x + 3re-arrange the first to make y the subject and substitute for y in the second:y = 1/2 (7 + 3x)1/2 (7 + 3x) = x2 - 2x + 3And solving the second:1/2 (7 + 3x) = x2 - 2x + 3→ 7 + 3x = 2x2 - 4x + 6→ 2x2 - 7x - 1 = 0→ x = 1/4 (7 ± √57)And substituting back into the (rearranged) first equation:y = 1/2 (7 + 3x)= 1/2 (7 + 3(1/4 (7 ± √57)))= 1/2 (28/4 + 3/4 (7 ± √57)))= 1/8 (49 ± 3√57)giving the two solutions:x = 1/4 (7 + √57) ≈ 3.637, y = 1/8 (49 + 3√57) ≈ 8.956x = 1/4 (7 - √57) ≈ -0.137, y = 1/8 (49 - 3√57) ≈ 3.294Note: the value of y is worked out once for each of the +/- of the √57; in this case +√57 for x leads to +√57 for y, and -√57 for x leads to -√57 for y. I showed the calculation in one for both.To check the result, a substitution can be made in the original equation 2:x = 1/4 (7 ± √57):y = (1/4 (7 ± √57))2 - 2(1/4 (7 ± √57)) + 3= 1/16 (7 ± √57))2 - 8/16(7 ± √57) + 48/16= 1/16 (49 ± 14√57 + 57 - 56 - ±8√57 + 48)= 1/16 (96 ± 6√57) [see below]= 1/8 (49 ± 3√57) as beforeIn simplifying ±14√57 - ±8√57 = (±14 - ±8)√57 the + and - signs of the 14 and 8 correspond to give:"+14" goes with "- +8" to give 14 - (+8) = 14 - 8 = +6"-14" goes with "- -8" to give -14 - (-8) = -14 + 8 = -6


What are all factors of 57 and 18?

The factors of 57 are 1, 3, 19, and 57The factors of 18 are 1, 2, 3, 6, 9, and 18


What are the common factors of 57 and 84?

The factors of 57 are:1, 3, 19, 57The factors of 84 are:1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84The common factors are:1, 3


What numbers go into 57?

1, 3, 19 and 57


What is 57 divided by 7?

8.1429


How 1 5 6 7 equals 21?

The answer is 6 / (1-5/7). 1- 5/7 = 2/7 6 / (2/7) = 6 * (7/2) = (6*7)/2 = 42/2 = 21. Simples!


What is the solution to the system of equations y equals 4x plus 8 and x squared plus 7x - 2 equals 0?

You havey = 4x + 8x² + 7x - 2 = 0The second is a quadratic involving only x so solve {2} first to find the x values, which can be substituted into the first to find the corresponding y value. x² + 7x - 2 = 0→ x = (-7 ± √(7² - 4×1×-2))/(2×1) = (-7 ± √57)/2→ x = (-7 - √57)/2→ y = 4 × (-7 - √57)/2 + 8 = -6 - 2√57or x = (-7 + √57)/2→ y = 4 × (-7 + √57)/2 + 8 = -6 + 2√57The solution is the two ordered pairs (x, y)::( (-7 - √57)/2, -6 - 2√57) and ((-7 + √57)/2, -6 + 2√57)


How do you subtract 3 and 1 sixth and 1 and 7 ninths?

19/6 = 57/18 16/9 = 32/18 57 - 32 = 25 25/18 = 1 and 7/18


What is 4 over 7 times 1 over 6?

4/7 * 1/6 = (4*1)/(7*6) = (2*1)/(7*3) = 2/21


How do you make 24 out of 1 2 6 7?

(7 + 1) × 6 ÷ 2 = 24.


How do you get 31 out of 1 2 6 and 7?

6 x (7 - 2) + 1 = 31


7 6 4 6 2 6 1 6 6 solve it?

7 6 4 6 2 6 1 6