6?!
1-2 2-3 3-4 4-5 5-6 6-7
The distance between (3, 7) and (-3, -1) is sqrt{[(3 - (-3)]2 + [7 - (-1)]2} = sqrt{[3 + 3]2 + [7 + 1]2} =sqrt{[6]2 + [8]2} = sqrt{36 + 64} = sqrt{100} = 10 units.
-1
Between the numbers 1 and 20 are the numbers 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, and 19.
1 and 7 divide evenly into 7.
7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.7*7 = 49 numbers.
-6
6
The odd numbers between 1 and 10 are 1, 3, 5, 7, and 9.
1
Using the distance formula from (3, 1) to (7, 1) is 4 units
The prime numbers between 1 and 10 are 2, 3, 5, and 7.
58
The prime numbers between 1 and 9 are 2, 3, 5, and 7.
There are 14 numbers between 1 & 100 that are divisible by 7.
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
The Prime numbers between 1 and 10 are 2, 3, 5, and 7.
The prime numbers between 1 and 10 are 1, 3, 5, and 7.