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3n + 2 + (3n + 3 - 3n + 1) =

3n + 2 + (3n + 3 - 3n + 1) =

3n + 2 + (4) =

3n + 6

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Q: How do you get this 3n plus 2 plus (3n plus 3 - 3n plus 1)?
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How do you get 3 to the power of n plus 2 plus (3 to the power of n plus 3 minus 3 to the power of n plus 1)?

3n+2 + (3n+3 - 3n+1) = 3n+1+1 + (3n+1+2 - 3n+1) = 3*3n+1 + (9*3n+1 - 3n+1)= (3+9-1)*3n+1 = 11*3n+1.


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The expression "3n plus 1" represents a mathematical equation where a number, 'n,' is multiplied by 3 and then 1 is added to the result. To find the value, you would substitute a specific number in place of 'n' and perform the calculation. For example, if 'n' was 2, the equation would be 3(2) + 1 = 7.


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