9 + (9/9) = 10
(99/9) - (9/9) = 10
[ (9 + 9 + 9 + 9 + 9 + 9 + 9 + 9 + 9) / 9 ] + (9/9) = 10
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.
There is only one three digit number for a gross, and that is 144.
Only in a single quadrant? No. A line can be in two, or in three, different quadrants.
No. You need at least four.
If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7. If the coins are a,b,and c, the combinations are a, b, c, ab, ac, bc, abc. If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.
999
No. A range can only be a single number.
Three different ways.
What are three different ways to make the number 15,638 with only hundreds,tens, and ones
20From Rafaelrz,The number of three digit permutations you can get from the four different digits3. 6. 7. 9, is given by:4P3 = 4!/(4-3)! = 4x3x2x1/1 = 24
It is possible to create infinitely many numbers, of infinitely many different lengths, using the digits of the given number. Using each of the digits, and only once, there are 5! = 120 different permutations.
111, 121, 212, 222
its impossible...bt we cn arrange only three 3rows using six circles.....with 3circles each......that too using sharing meathod
105=3*5*7it has to be only three factors and they are all prime105
998,000
Since there are only five different digits, a 6-digit number can only be generated if a digit can be repeated. If digits can be repeated, the smallest 6-digit number is 111111.
In this type of question, you need to fill out the largest digit you can, one at a time, from left to right. The largest digit you can use for the leftmost position, is 9, the largest digit for the next position is 9, etc.; in summary, the final result is:999999 (if you want AT MOST three different digits), or 999987 (if you want EXACTLY three different digits).