There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
There are: 12345C3 = 3.134847985*1011
Two . . . . . 38 and 83.
It can have 120 combinations . . .
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
There are 5C3 = (5*4*3)/(2*1) = 30 combinations.
22
22
100
It depends on the denominations of the coins and the exchange rate at the time.
It depends on the denominations of the coins and the exchange rate at the time.
It depends on the denominations of the coins and the exchange rate at the time.
12 how come
Six- hhh ttt hht tth hth tht
A lot
you wil have to figure it out, is it your homework?
It depends on the denominations of the coins and the exchange rate at the time.