There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
There are: 12345C3 = 3.134847985*1011
Two . . . . . 38 and 83.
It can have 120 combinations . . .
Just one. * * * * * Depends on how many numbers are on each ring. If there are x numbers, then the total number of combinations (actually they are permutations) is x*x*x or x3.
There are 5C3 = (5*4*3)/(2*1) = 30 combinations.
22
22
To determine the number of combinations of coins that can make one pound, we must consider the various denominations of coins in circulation. In the British currency system, there are eight common coins: 1p, 2p, 5p, 10p, 20p, 50p, £1, and £2. To calculate the number of combinations, we can use a mathematical approach called the "coin change problem," which involves dynamic programming to efficiently compute the possible combinations. The exact number of combinations would depend on the specific constraints and parameters set for the problem.
It depends on the denominations of the coins and the exchange rate at the time.
It depends on the denominations of the coins and the exchange rate at the time.
It depends on the denominations of the coins and the exchange rate at the time.
12 how come
Six- hhh ttt hht tth hth tht
A lot
*9.5
you wil have to figure it out, is it your homework?