If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7.
If the coins are a,b,and c, the combinations are
a, b, c, ab, ac, bc, abc.
If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.
There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
There are: 12345C3 = 3.134847985*1011
Two . . . . . 38 and 83.
It can have 120 combinations . . .
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
22
22
100
Six- hhh ttt hht tth hth tht
*9.5
you wil have to figure it out, is it your homework?
There are: 35C3 = 6545 combinations
I think there are 88 different combinations of coins that can make up 66 cents.
There are 6C3 = 20 such combinations.
There are 5C3 = 10 combinations.
There are 9C3 = 84 combinations.
You could make 10*10*10*26*26*26 combinations, or 17576000 combinations.