If the question concerned the number of combinations of three different coins, the answer is 23-1 = 7.
If the coins are a,b,and c, the combinations are
a, b, c, ab, ac, bc, abc.
If two of the coins are the same there are only 5 combinations and if all three are the same there are 3.
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There are 32C3 = 32*31*30/(3*2*1) = 4960 combinations. I do not have the inclination to list them all.
There are: 12345C3 = 3.134847985*1011
Two . . . . . 38 and 83.
It can have 120 combinations . . .
Just one. * * * * * Depends on how many numbers are on each ring. If there are x numbers, then the total number of combinations (actually they are permutations) is x*x*x or x3.