first make it fit into the standard formula.(y=mx+b)
y=1/1x-2
1/1 is the slope and -2 is the y intercept.
A line graph needs an equation. x-2 and x3 are expressions: neither is an equation.
No
A linear equation describes a line like 2x+1=y. If you were to graph that equation, then it would give you a line. A quadratic equation is like x^2+2x+1=y. Graphing this equation would give you a U shaped graph called a parabola.
y -x - 2 is not an equation (nor an inequality) and so there is no way to graph it.
Without an equality sign and not knowing the plus or minus values of 2y and 5 it can't be considered to be a straight line equation.
A line graph needs an equation. x-2 and x3 are expressions: neither is an equation.
Answer this question… What is the line of symmetry of the graph of the equation ? A. x = -2 B. x = -4 C. x = -16 D. x = -8
For the equation (9x^2)/(x^2+4)
5
No
An example of an equation with a degree greater than 1 is (y = x^2 - 4x + 4). This is a quadratic equation, and its graph is a parabola, which does not produce a straight line. Since its highest exponent is 2, it is classified as degree 2, and the graph will show a curved shape rather than a linear one.
That line is [ y = 2 cos(2x) ].
To find the equation of the line that passes through the point (2, 3) and is parallel to the line represented by the equation ( y = -2x + 3 ), we note that parallel lines have the same slope. The slope of the given line is -2. Using the point-slope form of the equation ( y - y_1 = m(x - x_1) ), where ( m = -2 ) and the point is (2, 3), the equation becomes ( y - 3 = -2(x - 2) ). Simplifying this gives ( y = -2x + 7 ).
The slope is -4
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
The equation you have given, y + 2 = 7, does not describe a line, it describes the number 5. You would not graph a single number, there is nothing to graph.
Y = 2 The graph is a horizontal line passing through the point Y=2 on the Y=axis. The line is parallel to the X-axis, and exactly 2 units above it everywhere.