It's the same as if you have anything else in the denominator. You can multiply both sides by the squared variable. Example (using "^" for "power"):
a = 1 / b^2
Multiply both sides by b^2:
Step 1: a b^2 = b^2 / b^2
Step 2: a b^2 = 1
Please use the correct terminology first. Replace "formula" with "equation" and it will seem more logical. But to answer your question, just subtract it from both sides and it should come out on the other side as the same squared variable, although now it is negative.
Look for points where the denominator is equal to zero. In other words, solve the equation: denominator = 0
You CAN have a variable in the denominator 1/x=1 is a simple example. The answer is x=1. The other is 10/x=2 x=5.
Algebraically manipulate the equation until you have the indicated variable on one side of the equation and all of the other factors on the other side.
In an equation b or any other letters usually denotes the unknown variable.
Please use the correct terminology first. Replace "formula" with "equation" and it will seem more logical. But to answer your question, just subtract it from both sides and it should come out on the other side as the same squared variable, although now it is negative.
substitution
Look for points where the denominator is equal to zero. In other words, solve the equation: denominator = 0
You CAN have a variable in the denominator 1/x=1 is a simple example. The answer is x=1. The other is 10/x=2 x=5.
Algebraically manipulate the equation until you have the indicated variable on one side of the equation and all of the other factors on the other side.
rRestate the equation as A = 3.14r2.The independent variable is the one you are given - in this case, 'r'.The dependent variable is the one you have to work out (it depends on the other variable). In this case, A.
You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.You find, or construct, an equation or set of equations which express the unknown variable in terms of other variables. Then you solve the equation(s), using algebra.
isolation of the variable means to get the variable on one side of the equation and the integers on the other side
There are several techniques to solve linear equations. One common technique is the elimination method, where you eliminate one variable by adding or subtracting equations. Another technique is substitution, where you solve one equation for a variable and substitute it into the other equation. You can also use matrices and row operations to solve linear equations.
Typically, you'll solve such an equation for one variable, in terms of the other variable. For example: y = 3x + 2 y = x squared - 5 y = 5 sin 3x Each of these is already solved for "y". If you substitute any value for "x" in this solution, you can calculate the corresponding value for "y".
In an equation b or any other letters usually denotes the unknown variable.
You solve the equation the same way as you would any other equation. Whether the variable is a fraction or otherwise will only become clear once you solve the equation. In other words, you don't initially KNOW whether the solution will be a fraction or not.