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What are the discontinuities of the function f(x) the quantity of x squared plus 5 x plus 6 all over 2 x plus 16.?
This is a rational function; such functions have discontinuities when their DENOMINATOR (the bottom part) is equal to zero. Therefore, to find the discontinuities, simply solve the equation:Denominator = 0 Or specifically in this case: 2x + 16 = 0
What are the vertical asymptotes of the function f(x) the quantity of 2 x plus 8 all over x squared plus 5 x plus 6?
They are at x = -3 and x = -2.
What is the discontinuity of the function f(x) the quantity of x squared minus 4 x minus 12 all over x plus 2?
In such cases, there is usually a discontinuity when the denominator is zero. In other words, solve for:x + 2 = 0
Can you Give an example of bounded function which is not Riemann integrable?
Yes. A well-known example is the function defined as: f(x) = * 1, if x is rational * 0, if x is irrational Since this function has infinitely many discontinuities in any interval (it is discontinuous in any point), it doesn't fulfill the conditions for a Riemann-integrable function. Please note that this function IS Lebesgue-integrable. Its Lebesgue-integral over the interval [0, 1], or in fact over any finite interval, is zero.
What is x squared over x squared?
Since x represents a single number, and it is x squared over x squared, then it will be the same numbers in the numerator and the denominator, no matter what value you replace x with (as long as you replace both x's with the same number). Therefore the answer is 1, unless the value of x is 0, in which case it is undefined. eg: 5 squared / 5 squared = 1 100 squared / 100 squared = 1 Try it with your calculator.
What are the discontinuities of the function f(x) the quantity of x squared plus 5 x plus 6 all over 2 x plus 16.?
This is a rational function; such functions have discontinuities when their DENOMINATOR (the bottom part) is equal to zero. Therefore, to find the discontinuities, simply solve the equation:Denominator = 0 Or specifically in this case: 2x + 16 = 0
What is the oblique asymptote of the function fx the quantity of x squared plus 7 x plus 11 all over x plus 5?
It is x - y + 2 = 0
What are the vertical asymptotes of the function f(x) the quantity of 2 x plus 8 all over x squared plus 5 x plus 6?
They are at x = -3 and x = -2.
What is the graph of the function fx the quantity of x squared plus 3 x minus 4 all over x plus 4?
It is the straight line through the points (0, -1) and (1, 0).
What value of a is required to normalize the function ?
To normalize a function, the value of a must be such that the integral of the function squared over its domain is equal to 1.
What is the discontinuity of the function f(x) the quantity of x squared minus 4 x minus 12 all over x plus 2?
In such cases, there is usually a discontinuity when the denominator is zero. In other words, solve for:x + 2 = 0
An exponential growth function describes an amount that decreases exponentially over time?
An exponential growth function actually describes a quantity that increases exponentially over time, with the rate of increase proportional to the current value of the quantity, resulting in rapid growth. The formula for an exponential growth function is y = a * (1 + r)^t, where 'a' is the initial quantity, 'r' is the growth rate, and 't' is time.
Is the quantity represented by x is a function that changes over time ie is not constant true or false?
True!
What is the simplified form of the quantity 15 x y squared over x squared plus 5x plus 6 all over the quantity 5 x squared y over 2x squared plus 7x plus 3?
((15xy2)/(x2+5x+6))/((5x2y)/(2x2+7x+3)) =(15xy2/5x2y)*(2x2+7x+3)/(x2+5x+6) =(3y/x)*(((2x+1)(x+3))/((x+2)(x+3) =(3y(2x+1))/(x(x+2)) =(6xy+3y)/(x2+2x)
What is the formula of a quadratic function?
-b + or - the square root on b squared - 4 times a times c over 2
Does the series sigma evaluated from n equals 1 to infinity of 1 over n times the quantity the natural log of n squared converge or diverge?
Diverge!
A squared over A to the fourth?
One over A squared or A to the negative 2.
