There are 3 values (1, 2, 3) for each of the 4 digits. Therefore, there are 3*3*3*3 or 81 four digit numbers that can be formed.
If you can repeat a digit, there are 27. If you can't repeat a digit, there are only 6.
60. There are 5 different choices for the first digit, four for the second digit, and three choices for the third digit. According to the fundamental counting principle, you multiply them together to get the total number of possible ways, and 5 x 4 x 3 = 60 Another way to think about it is 5!/3!
There are no two real numbers that will add to -9 and multiply to 81. Using complex numbers, the two numbers are: (-9/2 + i9/2√3) and (-9/2 - i9/2√3)
The final digit must be a 2 to form an even number. The first digit may be any of three remaining digits (1, 3, 5) while the second digit may be any of the two remaining digits. All together, that makes 3*2 = 6 distinct even numbers.
There are no such numbers.
you multiply 3 digit numbers by killing yourself and giving away body parts.
You multiply the one digit number on the bottom to every number on the top starting at the right and so on with every other number on the bottom.
4 options for the first digit, 3 options for the second digit, 2 options for the third digit. Multiply the number of options together, and you find how many 3-digit numbers you can get.
A 3 or 4 digit number.
Example: 222*12 222 3 digit * 13 2 digit ------- 666 Multiply 3 to all three twos +222 Multiply 1 to all three twos (skip spot) -------- 2886 Answer Add up
If multiplying 3 digit numbers with 2 digit numbers. For example; 345 x 92= First you will start with 2 by multiplying it by 5 then carry the 1 above the 4 then multiply the "2" with 4 then add the number on-top of the 4 which is 1 and it will give you 9. 4 x 2= 8+1=9. Then times the 2 by 3 which is 6. That is not your answer, yet. 690 plus the amount you get by multiplying 9 by every number, 5 then carry the number, 4 times 9, plus the number above it, then carry the 3 on top of the 3. Then add your total to 690 or what ever your equation is.
If this is a homework assignment, please consider trying it yourself first, otherwise the value of the reinforcement to the lesson offered by the homework will be lost on you.There are 60 possibilities that can be made for a three digit number using the numbers 2 4 6 8 and 9. (5 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit - multiply 5, 4, and 3, and you get 60.)To determine how many of these three digit numbers are smaller than 500, consider that, given 2 4 6 8 and 9, the first digit would have to be 2 or 4. That gives 2 choices for the first digit, 4 choices for the second digit, and 3 choices for the third digit. Multiply 2, 4, and 3, and you get 24.
If you multiply 2*9, you get 18. Multiply that by 10 to get a three digit number, and you get 180.
Here are two examples
840
By using the 3 digits of a number we can form 3 different two digit numbers. 3C2 = 3!/[(3 - 2)!2!] = 3!/(1!2!) = (3 x 2!)/2! = 3