substitute x = y and y = -x
Ex: y = x2 becomes
-x = y2
(-2,3) reflected over y = x is (3,-2) (400,-2) reflected over y = x is (-2,400) All you do is switch the ordered pair.
You switch the x and y coordinates of the line. In other words, (x,y) ---> (y,x). I hope this helps! :)
12
No
A straight line graph with negative slope slants downward from left to right.
To reflect a shape about a line, first identify the line of reflection and determine the perpendicular distance from each point of the shape to the line. Then, locate the corresponding point on the opposite side of the line at the same distance. Finally, connect these reflected points to form the new shape, ensuring that each point is equidistant from the line of reflection.
In mathematical terms, "reflect" refers to the process of flipping a shape or figure over a specific line, known as the line of reflection, to create a mirror image. This transformation alters the orientation of the figure while maintaining its size and shape. In coordinate geometry, reflecting a point across a line involves changing its coordinates based on the line's equation. For example, reflecting a point across the x-axis changes its y-coordinate to its negative.
No. You can reflect any shape about a line but if the resulting image is not the same as the original, that line is not a line of symmetry.
you put it at a 90 degree angle
negative 1
(-2,3) reflected over y = x is (3,-2) (400,-2) reflected over y = x is (-2,400) All you do is switch the ordered pair.
Negative association.
The visual elements of art is line shape positive negative
To reflect a point over the line ( y = x ), you swap the coordinates of the point. For example, if the original point is ( (a, b) ), its reflection over ( y = x ) will be ( (b, a) ). This process applies to any shape or set of points by reflecting each point individually.
That's the equation of a straight line. Unless the line is horizontal (for m = 0), the y-coordinate of the line will always be positive for part of the line, and negative for another part of the line.
x = negative 1 is a vertical straight line parallel to the y axis at x = -1 ; its slope is infinite
Find an equati find an equation for the line perpendicular to the line 8x - 8 y equals negative 2 having the same Y intercept as -6x + 2 y equals negative 8