How do you solve this system algebracally 9x plus 2y equals 5 and y 2x plus 3 equals 0?
If this was correctly written: Alternatively, you might have meant: 9x+2y=5 9x+2y=5y2x+3=0 2x+3y=09x+2y=5 27x+6y=152xy=-3 -4x-6x=09x+2y=5 23x=152x=-3/yx=15/239x+2y=52x+3/y=0 2(15/23)+3y=02(9x+2y)=(5) 30/23=-3y-9(2x+3/y)=0y=10/23, x= 15/2318x+4y=10-18x+-27/y=018x+4y=104y/y-10/y=27y/y-10=-31yy=10/319x+2(10/31)=59x=135/31x=.048, y=10/31