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How do you solve this system algebracally 9x plus 2y equals 5 and y 2x plus 3 equals 0?
If this was correctly written: Alternatively, you might have meant: 9x+2y=5 9x+2y=5
y2x+3=0 2x+3y=0
9x+2y=5 27x+6y=15
2xy=-3 -4x-6x=0
9x+2y=5 23x=15
2x=-3/y
x=15/23
9x+2y=5
2x+3/y=0 2(15/23)+3y=0
2(9x+2y)=(5) 30/23=-3y
-9(2x+3/y)=0
y=10/23, x= 15/23
18x+4y=10
-18x+-27/y=0
18x+4y=10
4y/y-10/y=27y/y
-10=-31y
y=10/31
9x+2(10/31)=5
9x=135/31
x=.048, y=10/31
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the answer
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