you need to know natural logarithms
3e to the 2x-1 power = 8
(2x-1) ln e = ln (8/3)
ln e = 1
(2x-1) = ln(8/3) = 0.98
2x = 1.98
x = 0.99
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E equals whatever you need it to to fit the equation.... for instance....3E=9....9/3=E.....E=3.. I'm only 12 so don't make fun of my answer..
-1
72(d^3)(e^2)72 is the LCM of 24 and 36.d^3 is the LCM of d and d^3.e^2 is the LCM of e^2 and e.
Let's represent Elga's age as x. Since Alvin's age is three times Elga's age, we can represent Alvin's age as 3x. The sum of their ages is 76, so we can create an equation: x + 3x = 76. Combining like terms, we get 4x = 76. Dividing both sides by 4, we find x = 19. Therefore, Elga's age is 19 years old.
Solve for e: 3d = 3e + 14 subtract 14 to both sides 3d - 14 = 3e divde by 3 to both sides d - 14/3 = e
Dumillinonagintanongentillion 1E8973 Trimillisexoctogintaoctingentillion 1E11661 Quadrimilliquattuordecicentillion 1E12345 Enneicosillion, 1E3,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,000,003 Dueicosedohectillion, 1E(3E(666)+3) Triotriacontetriahectillion, 1E(3E(999)+3) Femtekillillion, 1E(3E(15,000)+3) Vecekillillion, 1E(3E(30,000)+3) Pentecekillillion, 1E(3E(45,000)+3) Megillion, 1E(3E(3,000,000)+3) Gigillion, 1E(3E(3,000,000,000)+3) Terillion, 1E(3E(3E(12))+3) Petillion, 1E(3E(3E(15))+3) Exillion, 1E(3E(3E(18))+3) Zettillion, 1E(3E(3E(21))+3) Yottillion, 1E(3E(3E(24))+3) Xennillion, 1E(3E(3E(27))+3) Dakillion, 1E(3E(3E(30))+3) Hendillion, 1E(3E(3E(33))+3) Dokillion, 1E(3E(3E(36))+3) Tradakillion, 1E(3E(3E(39))+3) Tedakillion, 1E(3E(3E(42))+3) Pedakillion, 1E(3E(3E(45))+3) Exdakillion, 1E(3E(3E(48))+3) Zedakillion, 1E(3E(3E(51))+3) Yodakillion, 1E(3E(3E(54))+3) Nedakillion, 1E(3E(3E(57))+3) Ikillion, 1E(3E(3E(60))+3) Ikenillion, 1E(3E(3E(63))+3) Icodillion, 1E(3E(3E(66))+3) Ictrillion, 1E(3E(3E(69))+3) Icterillion, 1E(3E(3E(72))+3) Icpetillion, 1E(3E(3E(75))+3) Ikectillion, 1E(3E(3E(78))+3) Iczetillion, 1E(3E(3E(81))+3) Ikyotillion, 1E(3E(3E(84))+3) Icxenillion, 1E(3E(3E(87))+3) Trakillion, 1E(3E(3E(90))+3) Trakenillion, 1E(3E(3E(93))+3) Tracodillion, 1E(3E(3E(96))+3) Tractrillion, 1E(3E(3E(99))+3) Tekillion, 1E(3E(3E(120))+3) Hotillion, 1E(3E(3E(300))+3) Hodakillion, 1E(3E(3E(330))+3) Hotikillion, 1E(3E(3E(360))+3)
Triopentacontillion, 1E((3E159)+3) Killavecillion, 1E((3E3030)+3) Mejillion, 1E(3E(3E(3,000,000))+3) Bejillion, 1E(3E(3E(6,000,000))+3) Trejillion, 1E(3E(3E(9,000,000))+3) Tejillion, 1E(3E(3E(12,000,000))+3) Pejillion, 1E(3E(3E(15,000,000))+3) Exejillion, 1E(3E(3E(18,000,000))+3) Zejillion, 1E(3E(3E(21,000,000))+3) Yejillion, 1E(3E(3E(24,000,000))+3) Nejillion, 1E(3E(3E(27,000,000))+3) Dakejillion, 1E(3E(3E(30,000,000))+3) Hendejillion, 1E(3E(3E(33,000,000))+3) Dokejillion, 1E(3E(3E(36,000,000))+3) Tradakejillion, 1E(3E(3E(39,000,000))+3) Tedakejillion, 1E(3E(3E(42,000,000))+3) Pedakejillion, 1E(3E(3E(45,000,000))+3) Exdakejillion, 1E(3E(3E(48,000,000))+3) Zedakejillion, 1E(3E(3E(51,000,000))+3) Yodakejillion, 1E(3E(3E(54,000,000))+3) Nedakejillion, 1E(3E(3E(57,000,000))+3) Ikejillion, 1E(3E(3E(60,000,000))+3) Ikenejillion, 1E(3E(3E(63,000,000))+3) Icodejillion, 1E(3E(3E(66,000,000))+3) Ictrejillion, 1E(3E(3E(69,000,000))+3) Icterejillion, 1E(3E(3E(72,000,000))+3) Icpetejillion, 1E(3E(3E(75,000,000))+3) Ikectejillion, 1E(3E(3E(78,000,000))+3) Iczetejillion, 1E(3E(3E(81,000,000))+3) Ikyotejillion, 1E(3E(3E(84,000,000))+3) Icxenejillion, 1E(3E(3E(87,000,000))+3) Trakejillion, 1E(3E(3E(90,000,000))+3) Trakenejillion, 1E(3E(3E(93,000,000))+3) Hotejillion, 1E(3E(3E(300,000,000))+3) Astillion, 1E(3E(3E(3E12))+3) Dastillion, 1E(3E(3E(6E12))+3) Trastillion, 1E(3E(3E(9E12))+3) Tastillion, 1E(3E(3E(1.2E13))+3) Pastillion, 1E(3E(3E(1.5E13))+3) Pastavecillion (yum!), 1E(3E(3E(1.5E13)+30)+3) Exastillion, 1E(3E(3E(1.8E13))+3) Zastillion, 1E(3E(3E(2.1E13))+3) Yastillion, 1E(3E(3E(2.4E13))+3) Nastillion, 1E(3E(3E(2.7E13))+3) Nastihotillion, 1E(3E(3E(2.7E13(+300)))+3) Dakastillion, 1E(3E(3E(3E13))+3) Ikastillion, 1E(3E(3E(6E13))+3) Trakastillion, 1E(3E(3E(9E13))+3) Hotastillion, 1E(3E(3E(3E14))+3) Potastillion, 1E(3E(3E(1.5E15))+3) Lunillion, 1E(3E(3E(3E15))+3)
-75=3e You divide each side by 3, to get e on a side by itself. -75/3=3e/3 Doing that cancels out the 3 on the right side. And -75/3 equals -25 -25=e Then you check your work, and plug in -25 as e in the original problem. -75=3(-25) which ends up being -75=-75 which is true.
The biggest number referred to regularly is a googolplex (10googol), which works out as 1010^100
3e-16 = -13
3e+23
Hi. The easiest it probably this. It is played in the right hand. The Number is the finger (IE 1 is the thumb, 2 is the index finger and so on. ) and the letter is the note. 3E, 2D, 1C, 2D, 3E, 3E, 3E, 2D, 2D, 2D, 3D, 5G, 5G. 3E, 2D, 1C, 2D, 3E, 3E, 3E, 1C, 2D, 2D, 3E, 2D, 1C. Hope this is what you were looking for!
10
3E is nothing but AC economy class
3e+7e = 10e
9 e3x = 27 ex-1e3x / ex-1 = 27/9 = 3e(3x - x + 1) = 3e2x+1 = 32x + 1 = ln(3) = 1.098612x = 0.09861x = 0.09861 / 2 = 0.04931(rounded)