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How do you factor xsquared plus 16?
(x - 4i)(x + 4i) where i is the square root of -1
What is 12 fewer hats than four times number i?
To solve this problem, we first need to understand that "four times the number i" can be represented as 4i. Then, to find "12 fewer hats than 4i," we subtract 12 from 4i to get 4i - 12. Therefore, "12 fewer hats than four times the number i" is represented by the expression 4i - 12.
Find the complex fourth root of 256i Express your answer in a plus bi form?
The four roots of 4√256 are {4, -4, 4i, and -4i}. Note that two of them are real numbers and the other two are pure imaginary, therefore 0 + 4i is the same as just 4i
How do you simplify the expression 3i x -4i?
7
What is the conjugate of the complex number 7-4i?
To get the conjugate simply reverse the sign of the complex part. Thus conj of 7-4i is 7+4i
2 plus 4i - 7 plus 4i?
(2 + 4i) - (7 + 4i) = -5 2 + 4i - 7 + 4i = -5 + 8i
What is the conjugate of -6 plus 4i?
-6-4i.
How do you solve 3 x squared plus 51 equals 6 x?
3x2 + 51 = 6x Rewrite the equation so that it equates to zero 3x2 - 6x + 51 = 0 Simplify by dividing by 3 x2 - 2x + 17 = 0 Then use the quadratic formula x = {2 ± √[(-2)2 -(4x1x17)]} ÷ 2 = { 2 ± √-64} ÷ 2 = 1 ± 4i Then x = 1 + 4i and x = 1- 4i
What is the complex form of 4 plus 4i plus 4 plus 6i?
the problem: what is 4 + 4i + 4 + 6i what you do is add the real and imaginary parts, thus: 4+4 and 4i+6i = 8+10i answer.
What is the conjugate of 3 plus 4i?
When finding the conjugate of a binomial, you just reverse the sign. So the conjugate of 3+4i is 3-4i.
How do you factor xsquared plus 16?
(x - 4i)(x + 4i) where i is the square root of -1
What is x squared plus 80 equals 0?
It's a second degree equation in 'x' that has no real solution. No real number in the place of 'x' can make that equation a true statement. There are only two "imaginary" numbers that 'x' can be: + 4i sqrt(5) - 4i sqrt(5)
Find the conjugate of 8 plus 4i.?
The conjugate of a complex number is obtained by changing the sign of its imaginary part. For the complex number (8 + 4i), the conjugate is (8 - 4i).
How do you solve 7-4i-6-8i in complex number I need work answer choices are A 74-32i B -98 plus 56i C 10 plus 80i D -74-32i?
It is D.
What is 12 fewer hats than four times number i?
To solve this problem, we first need to understand that "four times the number i" can be represented as 4i. Then, to find "12 fewer hats than 4i," we subtract 12 from 4i to get 4i - 12. Therefore, "12 fewer hats than four times the number i" is represented by the expression 4i - 12.
What is 2-4i over 4 plus 2i put in the form of a plus bi?
To solve this type of problem, multiply both the numerator and denominator by the conjugate of the denominator. (2 - 4i) / (4 + 2i) = (2 - 4i)(4 - 2i) / (4 + 2i)(4 - 2i) then expand all the terms, and simplify. = (8 - 20i + 8i2) / (16 - 4i2) = (8 - 20i - 8) / (16 + 4) = -20i / 20 = -i Which in the required answer format becomes, 0 + i.
What is the product of these complex numbers (3-4i)(1-i)?
(3-4i)(1-i) = (3x1) + (3 x -i) + (-4i x 1) + ( -4i x -i) = 3 - 3i -4i -4 = -1 - 7i
