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the problem: what is 4 + 4i + 4 + 6i
what you do is add the real and imaginary parts, thus:
4+4 and 4i+6i = 8+10i answer.
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What is 4 plus 6i plus 7 plus you simplified in standard form?
The expression to simplify is 4+6i+7 Answer: 6i + 11
What is the equivalent form of 10 plus 6i and 7 plus 2i?
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
What is the complex conjugate complex number-8-6i?
-6i-8
Is -6i a complex number?
A complex number is x+iy and -6i is 0-6i or 0-i6 I would then answer yes.
What is the complex conjugate complex number 8 6i?
Since you didn't show an operator, we'll use: 1. 8-6i 2. 8+6i 3. 8 times 6i = 48i The complex conjugates are: 1. 8+6i 2. 8-6i 3. -48i
What is the complex conjugate of 2-6i?
7
What is 4 plus 6i times -7 plus you simplified in standard form?
(4 + 6i)*(-7) = -28 - 42iAnd just because i = sqrt(-1), I am not something that you can multiply or simplify.
If Vector B is added to Vector A, the result is 6i+j. If B is subtracted from A, the result of -4i+7j. What is the magnitude of A?
11
8 plus 6i-2 plus 3i?
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
How do you rationalize complex numbers?
you must multiply by the conjagate. which is the denominator with the middle sign changed....(5+6i)...conjagate= (5-6i)....
What is the complex conjugate of a plus bi?
The complex conjugate of a+bi is a-bi. This is written as z* where z is a complex number. ex. z = a+bi z* = a-bi r = 3+12i r* = 3-12i s = 5-6i s* = 5+6i t = -3+7i = 7i-3 t* = -3-7i = -(3+7i)
What is The square root of 25-2times the square root of -36 plus the square root of four - the square root of 121?
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
