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Equations of the form z^4+az^2+a_0 are known as biquadratic equations. They are quartic equations. In general they can be solved by reducing them to a quadratic equation where x=z^2 is the variable. Then you can use the quadratic formula or factor. So plugging in x to the biquadratic giives us x^2+ax+a_0.

Q: How do you solve a biquadratic equation?

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A quartic is a polynomial of degree 4, meaning the highest exponent is 4. Biquadratic can mean the same thing, but most mathematicians use the term biquadratic to refer to an equation of degree 4 with no odd powers. So for example we cannot have an x3 term. An example of a biquadratic is: x4 +x2 + 22=0

it is not an equation (there no equality in it!)

Solve the equation for x, and enter your answer in the box below.

variable equation solve it test it

Use a variable to represent the unknown. 'Translate' the words to math symbols and write an equation to solve. Solve the equation. Check.

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A quartic is a polynomial of degree 4, meaning the highest exponent is 4. Biquadratic can mean the same thing, but most mathematicians use the term biquadratic to refer to an equation of degree 4 with no odd powers. So for example we cannot have an x3 term. An example of a biquadratic is: x4 +x2 + 22=0

A biquadratic is a polynomial which involves only the second and fourth powers of a variable.

Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.

you don't answer an equation, you solve an equation

it a biquadratic bezier patch.

Jean-Marc Deshouillers has written: 'On sums of sixteen biquadrates' -- subject(s): Biquadratic Equations, Equations, Biquadratic

solve it

If you solve such an equation for "y", you get an equation in the slope-intercept form.

It is not an equation if it does not have an equals sign. You could simplify it but not solve it.

How do you use division to solve a multiplication equation?Answer this question…

you can only solve for one in an equation so it can equal something

There is no such thing as "solving integers". You can solve an equation, which means finding all the unknowns in that equation, but you can't solve an integer.