It is not an equation if it does not have an equals sign. You could simplify it but not solve it.
3q+11+8q>99
3q+11+8q>99
3q + 5 + 2q + 5 = 65 5q + 10 = 65 5q = 55 q = 11 Check it. 33 + 5 + 22 + 5 = 65 It checks.
3q = 18 q = 6
steps to solve 4(3q-q): =(4)(3q+-q) =(4)(3q)+(4)(-q) =12q-4 answer: 8q
we have -3q=5 so dividing both sides of the equation by -3 yields q=-5/3.
(3)(q-11) = 3q-33
6p=3q
If -3q + 4 = 13 then 3q = -9 : q = -3 If 6q = 13 then q = 13/6 = 2 1/6 The question contains an anomaly and is invalid.
3q + 11 + 8q > 99 11q + 11 > 99 Subtract '11' from both sides 11q > 99 - 11 11q > 88 Divide both sides by (+)11 q > 88/11 q > 8 ('q' is greater than '8'). Verification When q = 7 (8) 11(9) = 99 > 88 (True) 1
2p + 3q = 13, 5p - 4q = -2 Multiply the first equation by 4 and the second by 3 and add them, which gets rid of the q: 8p + 15p = 52 - 6, and 23p = 46, so p=2. Plug that into the first equation to find q: 4 + 3q = 13, so q=3. Test your answers in the second equation to be sure: 5(2) - 4(3) = 10-12 = -2. It checks. So p=2, q=3.
Without an equality sign the given expression can't be considered to be an equation.