cant explain it but i can give you an example: equation 1: 14x+2y=20 equation 2: 5x-y=8 First step is to get on of the varibles to cancel out so leave the first eqation alone put change the second in this problem so: 5x-y=8 becomes 2(5x-y=8) which equals 10x-2y=16 the next step is to subtract them like this: 14x+2y=20 10x-2y=16 the +2y and the -2y cancel out so the answer then would be 4x=4 which means 1=x then you plug the answer 1 in for x into on of the equations to find y so: 5(1)-y=8 = 5-y=8 =-y=3 =y=-3 so the system answer is (1,-3)
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there are three methods: combination, substitution and decomposition.
It is not always the best method, sometimes elimination is the way you should solve systems. It is best to use substitution when you havea variable isolated on one side
Use the substitution method to solve the system of equations. Enter your answer as an ordered pair.y = 2x + 5 x = 1
You can use a graph to solve systems of equations by plotting the two equations to see where they intersect
Multiply every term in both equations by any number that is not 0 or 1, and has not been posted in our discussion already. Then solve the new system you have created using elimination or substitution method:6x + 9y = -310x - 6y = 58